D = (-(3+a))2-4.1.9 = 0
9 + 6a +a2 -36 =0
a2+6a-27=0
a=-9 atau a=3
9.(-3) -> 9.(-3) = 27
9 + (-3) = 6
2. y=y
x2 - 3x + p = px-3
x2 - 3x - px +p = -3
x2 - (3+p)x + p +3 = 0
a = 1, b = -(3+p), c = p+3
D = b2-4.a.c
b2 - 4.a.cc < 0
(-(3+p))2 - 4.1.(p+3) < 0
9 + 6p + p2 -(4p+12) < 0
9 + 6p+p2 - 4p - 12 < 0
p2 + 2p - 3 <0
(p+3)(p-1) < 0
p = -3 p = 1
Sehingg, -3 < p < 1